i need help again ! can anyone help ?
What is the percentile for data value 6 in the following data set?
4 13 8 6 4 4 13 6 4 13 2 13 15 5 9 4 12 8 6 13
40
35
25
62
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OpenStudy (anonymous):
one thing...
Didn't get the question yet..../// :/
Specific please...
OpenStudy (anonymous):
@harishk idk how to i copied and pasted
OpenStudy (anonymous):
Order the values:
2 4 4 4 4 4 5 6 6 6 8 8 9 12 13 13 13 13 13 15
There are 20 values.
7 values are less than 6.
OpenStudy (anonymous):
Can you tell me what you think the percentile rank is?
OpenStudy (anonymous):
like the definition ?
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OpenStudy (anonymous):
no, the number :)
OpenStudy (anonymous):
would it be 12 ?
OpenStudy (anonymous):
no, 6
OpenStudy (anonymous):
so it would be the median ?
OpenStudy (anonymous):
So what would the percentile rank of 6 be?
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OpenStudy (anonymous):
im not sure
OpenStudy (anonymous):
okay :)
OpenStudy (anonymous):
i can give you an example with a different number
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
Percentile rank of 14 is (9/15)(100) = 60 or 60th percentile
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OpenStudy (mrnood):
@pinkbubbles
why 9/15?
12/20 is more intuitive (I acknowledge it is the same number...)
OpenStudy (anonymous):
Okay! :) @MrNood
OpenStudy (anonymous):
OpenStudy (anonymous):
ugh im sorry i dont get this at all !
OpenStudy (anonymous):
it's fine! :D
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OpenStudy (anonymous):
\[\frac{ number of scores below x }{ n }\times100 = percentile rank\]
So x is 6 andnumber of scores below 6 is 7
OpenStudy (anonymous):
so 7(6)/n(100)=percentile rank
OpenStudy (anonymous):
\[\frac{ 7 }{ 6 }\times100=? \]
OpenStudy (anonymous):
Correct! :D
OpenStudy (anonymous):
116.67 ?
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OpenStudy (anonymous):
but that isnt one of the choices
OpenStudy (anonymous):
Oops sorry i made a mistake so sorry
OpenStudy (anonymous):
no its fine
OpenStudy (anonymous):
\[\frac{ 7 }{ 20 }\times100=\]
OpenStudy (anonymous):
so 35 ?
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OpenStudy (anonymous):
Right! =)
OpenStudy (anonymous):
Do you understand the formula now?
OpenStudy (anonymous):
@dani_00
OpenStudy (anonymous):
oh sorry ! yes i do thank you !!
OpenStudy (anonymous):
@pinkbubbles
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OpenStudy (anonymous):
Welcome! If you need anymore help i'm here just tag me! :D