A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?

Question

anonymous · Answer

so would it be 4/9 ? cause i did 1 + 3 and kept the denominator the same.

anonymous · Answer

The sum of all the probabilities must be 1. What do think the answer is?

anonymous · Answer

why would it be 5/9 ? @pinkbubbles

anonymous · Answer

P(orange) + P(strawberry) + P(pineapple) = 1
1/9 + 3/9 + P(pineapple) = 1
Understand?

anonymous · Answer

i think so. so would my answer then be 2/9?

anonymous · Answer

Not quite.$$\frac{ 1 }{ 9 } + \frac{ 3 }{ 9 } + P(pineapple) = \frac{ 9 }{ 9 }$$What is P(pineapple)?

anonymous · Answer

oh I think I got it now, so pineapple is 5/9 right?

anonymous · Answer

Bingo!! Well done.

anonymous · Answer

thank you, I really understand it now! :)

anonymous · Answer

That's the most important thing. Keep up the good work.