Question

How do we solve for this: lim(t->0) (tan2t)/3t

Answer 1

if we do a direct substitution we get 0 /0
so apply l'hopital's rule

Answer 2

giving 2 sec^2 2t / 3

Answer 3

@welshfella Oh got it, okay thanks!

Answer 4

- that isnt the answer
thats just the result of differentiating the top and bottom of the function.

Answer 5

if we now substitute directly we have
2 * (1) / 3 = 2/3

required limit is 2/3

Answer 6

- perhaps you've worked that out already