Question

IS ANYOME GOOD AT FINDING DERIATIVES FOR LN?! Please I need help as soon as possible! :(

Answer 1

post it up

Answer 2

Ok

Answer 3

y=ln(1-x/(x+2)^5)

Answer 4

\[y=\ln [1 -\frac{ x }{(x+2)^{5}}]\]

Is that it?

Answer 5

No sorry my computer is messed up, the 1-x is the numerator, and the denominator is as you out it. Ln is correct too

Answer 6

Put*

Answer 7

@alekos

Answer 8

\(\large y=ln \frac{1-x}{(x+2)^5} \)

assuming that you know that \(\large (log \ u(x))' = \frac{1}{u} u'\)

then look also at \(\large ln \frac{a}{b} = ln \ a - ln \ b\) and similar properties of logs; and maybe split this up a bit before you start...

Answer 9

yeah, thanks Irish Boy. I reckon do the properties of logs....

Ln(1-x) - Ln(x+2)^5
= Ln(1-x) - 5Ln(x+2)

the rest is easy because the derivative of Lnx is 1/x

Answer 10

@alekos look good