Chem problem Will post it in a bit.
Here it is
@Rushwr
@Cuanchi
Thought it was a good idea to post this. it's kind of tricky
Do you include the solids in the Keq? why?
@Cuanchi \[K _{eq} = \frac{ [C]^x[D]^y }{ [A]^c[B]^d }\] they don't give us any information about the Keq, but i totally misread it, like i figure that solids wont be included in that but the explanation was "their concentarations don't change much" but isn that the same for liquids?
Yes pure liquids (l) and solids (s) are not included in the equilibrium constant, only gases (g) and aqueous (aq) are included.
from which manual did you got that question?
that has to do with how [ ] changes right?
the books are called McGraw-Hill's 500 questions if you guys are interested
i didn't even read the question and then thought oh if I add more of the solid should increase the rate.
Happens to everyone, I know I like to think liquids count for a lot more stuff than they actually do. But going back to the question so the only compound that is included is the Cl2 meaning that Keq=1/[Cl2]. I think that when Keq is greater than one there is a lot of product so the reaction wants to go left but when Keq is less than one the reaction goes to the right (I think that's right).
There's Keq and then Kc something like that.
Don't remember off the top of my head; i believe that it's Kq not Kc Something like when Q < K rxn goes to the right. Q>K rxn goes to left.
So Tara SnCl2 would be considered a pure liquid? Originally I thought it was [SnCl2]/[Cl2]
Found a pretty good link for the rules for K and Q partly because I am always forgetting them http://chemwiki.ucdavis.edu/Physical_Chemistry/Equilibria/Chemical_Equilibria/The_Reaction_Quotient/Difference_Between_K_And_Q Also why pure liquid for SnCl2 I thought that was a solid?
@taramgrant0543664 i meant to put SnCl4 in the expression. mistake lol
Haha mistakes happen to everybody!! The SnCl4 I wouldn't but it in the equation since you don't put liquids into the equation and it wouldn't count in the equilibrium since the solution has to either be aqueous or a gas
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