i need some help on proportions
If 2 over 3 ton of gravel covers 3 over 4 of a driveway, how many tons of gravel are required to cover the entire driveway?
it depends on the driveway length
idk its 7th grade math
Are you given the length of the driveway?
no
Oh, no need for this length..... t- ton of gravel d-driveway \(\large\color{black}{ \displaystyle \frac{2}{3}t=\frac{3}{4}d }\)
So, you need to solve for d.
yes that is correct
(multiply both sides times 4/3) \(\large\color{black}{ \displaystyle \frac{2}{3}t\color{red}{\times \frac{4}{3}}=\frac{3}{4}d\color{red}{\times \frac{4}{3}} }\)
idk how but your supost to do it with proportions
ok i get it
good, so what will be your answer?
idk honestly im lost but i can multiply fractions but itll take me a sec
idk i got 1 1/3 and 1
\(\large\color{black}{ \displaystyle \frac{2}{3}t=\frac{3}{4}d }\) in this proportion, t is tons of gravel, and d is the driveway. \(\large\color{black}{ \displaystyle \frac{2}{3}t\color{red}{\times \frac{4}{3}}=\frac{3}{4}d\color{red}{\times \frac{4}{3}} }\) i multiplied times 4/3 to isolate the d (the driveway), because you have to find the number of tons of gravel per a driveway. \(\large\color{black}{ \displaystyle \frac{2}{3}t\color{red}{\times \frac{ 4}{3}}=\frac{\cancel3}{\bcancel4}d\color{red}{\times \frac{\bcancel 4}{\cancel3}} }\) 4's and 3's cancel. \(\large\color{black}{ \displaystyle \frac{2}{3}t\color{red}{\times \frac{ 4}{3}}=d }\) and then multiply the fractions \(\large\color{black}{ \displaystyle \frac{2}{3}\times \frac{ 4}{3} \times t=d }\) \(\large\color{black}{ \displaystyle \frac{2\times4}{3\times3}t=d }\)
and then what do you get? (how many tons of gravel, t, do you need, in order to cover the driveway, d?)
8/6 or 1 1/3
3×3=9, (not 6)
so it is 8/9
oh my bad so 8/9
ya lol
so you need 8/9ths tons of gravel to cover a driveway
yw.
can you help me with one more
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