Question

A total of $20,000 is invested in two bonds that pay 8% and 9.5% in interest. The annual interest is $1675. How much is invested in each bond?

Answer 1

@Deeezzzz

Answer 2

x = amount invested at 8%
20000-x= amount invested at 9.5%

Answer 3

How does 2000-x equal to 9.5%?

Answer 4

it's 20000-x

Answer 5

Yeah sorry that.

Answer 6

.08x = interest earned on 8% investment
.095(20000-x)= interest earned on 9.5% investment

Answer 7

Total interest earned is $1675
Write and solve the equation that says the sum of the two interest amounts is1675

Answer 8

.08x + .095(20000-x) = $1675

Answer 9

Solve it.

Answer 10

0.08x + 0.095(20000-x) = 1675
0.08x + 1900 + 0.095x = 1675
0.175x + 1900 = 1675
0.175x = -375
2142?

Answer 11

-.095x

Answer 12

For what? Why is it negative?

Answer 13

\[.095(20000-x)=1900-.095x\]

Answer 14

oh yeah

Answer 15

0.705x = 1675
x = 2375

Answer 16

\[.08x+.095(20000-x)=1675\]
\[.08x+1900-.095x=1675\]
\[-.015x+1900=1675\]
\[-.015x=-225\]
\[\frac{-.015x}{-.015}=\frac{-225}{-.015}\]
\[x=15000\]

Answer 17

I am sorry. I am really tired so I can't focus as usual. I have to get it on track. :)

Answer 18

So 15000 was invested at 8%
20000-x=5000 = amount invested at 9.5%

Answer 19

x= 15000

Answer 20

So those are the answers right?