Solve by using the perfect squares method.
x2 + 8x + 16 = 0
A.
–2
B.
4
C.
–4
D.
2
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OpenStudy (anonymous):
@Nnesha
OpenStudy (anonymous):
isnt it -4
OpenStudy (anonymous):
thats what i got
Nnesha (nnesha):
how did you get -4 show your work :=)
Nnesha (nnesha):
solve by using the *perfect squares method* what waz your first step ? :=)
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OpenStudy (anonymous):
sorry opn studys acting up
OpenStudy (anonymous):
See how the coefficient on x^2 is a perfect square? (it is 1, which is 1 squared).
See also how the constant term is a perfect square? (it is 16, which is 4 squared).
Notice also that if you take the coefficient on the middle term (8) and divide it by 2 (giving you 4) and then square it, you get the product of the 1 and the 16? (4 squared is 16)
That tells us this trinomial is a perfect square. (x+4)^2
By the zero product property, we know that x+4=0, so x=-4
Nnesha (nnesha):
nice
OpenStudy (anonymous):
is it right
Nnesha (nnesha):
yep
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