John was visiting three cities that lie on a coordinate grid at (-4, 5), (4, 5), and (-3, -4). If he visited all the cities and ended up where he started, what is the distance he traveled? Round your answer to the nearest tenth. (like 3.2 or 5.7)
Find the distance between the points using the distance formula \[\large \bf d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\]
okay
would it be 16 ?
the points (-4, 5) and (4, 5) lay on the same line y=5, so the distance between these points is just: 4-(-4) So you know the first side of 8 units. You do however need the distance formula for two other sides. 1. Distance between (-3, -4) and (-4, 5) 2. Distance between (-3, -4) and (4, 5)
Distance between (-3, -4) and (-4, 5) = \(\small\color{black}{ \displaystyle \sqrt{(-4-5)^2+(-3--4)^2}=?}\) ------------------------------------------------------- Distance between (-3, -4) and (4, 5) = \(\small\color{black}{ \displaystyle \sqrt{(-4-5)^2+(-3-4)^2}=?}\)
after you find all sides, add them up
would it be 16?
I had gotten 12 but I know definitely it isn't the answer for the question
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