Did i do this right??
(x-^2y^-4x^3)-^2
First remove the parenthesis now we use the
ab = 1/ab property
x^-2 = 1/x^2
now we have a positive exponent x^2.
Next y^-4 = 1/y^4 now we have three positive exponents now we need to make the negative 2 positive. -2= 1/-2
now we have x^2y^4x^3 add the like terms x^2+ x^3 = x^5
(x^5y^4)^2

Question

Did i do this right??
(x-^2y^-4x^3)-^2
First remove the parenthesis now we use the
ab = 1/ab property 
 x^-2 = 1/x^2 
now we have a  positive exponent x^2. 
Next y^-4 = 1/y^4 now we have three positive exponents now we need to make the negative 2 positive. -2= 1/-2
now we have  x^2y^4x^3 add the like terms x^2+ x^3 = x^5 
(x^5y^4)^2

anonymous · Answer

have u ever heard PEMDAS in math

anonymous · Answer

Yes i did

anonymous · Answer

use that to solve it did u do that

anonymous · Answer

I believe so.

mathstudent55 · Answer

Is this the problem?

$\Large (x^{-2}y^{-4}x^3)^{-2}$

anonymous · Answer

do it again and show me the steps and ill correct u if ur wrong