Please help will fan and medal!
h of the following functions represents a geometric sequence? Why? a. The function f(x) = x^3 represents a geometric sequence because each term is cubed to make it greater. b. The function f(x) = 4x represents a geometric sequence because each term is the next higher multiple of 4. c. The function f(x) = 4x- 4 represents a geometric sequence because each term is 4 more than the previous term. d. The function f(x) = 4^x represents a geometric sequence because each term is 4 times as great as the previous term.
soo what do u know about the sequence
@jamesr lol she's off line
ok less work 4 me
@jamesr lol she's back
Sorry my computer died
Is it a?
ok, i am back had to unload some packages....
An exponental function represents a geometric sequence. An exponential function is an form of: \(y=b^x\) or \(y=a(b)^x\)
so it is A?
-100 is the y intercept and if you change it 25 it would go up i believe it is a
it is not A.
An exponental function represents a geometric sequence. An exponential function is an form of: y=b\(^x\) or y=a(b)\(^x\) ---------------------------------------------------- why is this so that exponential function represents a geometric sequencet? A geometric sequence is a sequence that follows a pattern of multiplying. In other words you multiply the first term \(a_1\) by common ratio \(\rm r\) to get the the second term \(a_2\). Then you multiply the second term \(a_2\) by common ratio \(\rm r\) to get to the third term \(a_3\). (AND SO ON......) For example: \(3,~~6,~~12,~~24,~~48~...\) You can see that the sequence starts from 3, so \(a_1=3\) And that you multiply times 2, so \(\rm r\)=2. Now! We can represent the same thing exponentially.... how (read this while I am typing)
So, exponential function y=a(b)\(^x\) (we will refer to the same example) we can write y=3(2)\(^{x-1}\) and it will be equivalent. when x=1 you get: f(1)=3(2)\(^{1-1}\) = 3(2)\(^{0}\) =3 (and that is \(a_1\)) when x=2 you get: f(2)=3(2)\(^{2-1}\) = 3(2)\(^{1}\) =3•2=6 (and that is \(a_2\)) when x=3 you get: f(3)=3(3)\(^{3-1}\) = 3(2)\(^{2}\) =3•4=12 (and that is \(a_3\)) when x=4 you get: f(3)=3(3)\(^{4-1}\) = 3(2)\(^{3}\) =3•8=24 (and that is \(a_4\)) and so forth
So it is definitely not a. Could it be B or D?
do you know what arithemtic sequence is?
I'm leaning more towards b.
do you know what an arithmetic sequence is?
It's a sequence where the difference is constant
yes, where you add or subtract the same number.
i have a feelin she guessin lol
And this (arithmetic sequence) is represented by linea function (in a form of y=mx+b)
linear*
You are not being any help Jamesr so if you do not have anything helpful to say, please leave.
So, option B y=4x when x=1, you get 4•1=4 when x=2, you get 4•2=8 when x=3, you get 4•3=12 when x=4, you get 4•4=16 when x=5, you get 4•5=25 so this function (for natural number x values) would represent an arithemtic sequence with the first term 4 and a common difference of 4.
And any other function in a form of y=mx+b is an arithmetic sequence (roughly speaking, of course)
So tell me now, is B the correct option or not?
Not
yes, B is not the answer.
And I'm guessing D isn't either.
why not?
Sorry *C and because its a form of mx+b
you need a function that represents a geometric sequence (not arithmetic sequence).
So d?
yes
Alrighty. Thanks!
im sorry i was gonna help but @SolomonZelman beat me to it
LOL @jamesr leave if you don't have nothing good ta say
im sorry i am im just an donkey term some times
LOL u said donkey
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