Question

Two quadratic functions are shown.

Function 1:
f(x) = 2x2 − 8x + 1 Function 2:

x g(x)
−2 2
−1 −3
0 2
1 17


Which function has the least minimum value and what are its coordinates?
Function 1 has the least minimum value and its coordinates are (0, 1).
Function 1 has the least minimum value and its coordinates are (2, −7).
Function 2 has the least minimum value and its coordinates are (0, 2).
Function 2 has the least minimum value and its coordinates are (−1, −3).

Answer 1

@campbell_st

Answer 2

any help

Answer 3

ok.... in the 2nd function, g(x) what is the lowest value in the g(x) column... and what x value is associated with it

Answer 4

ok is it -2,2 @campbell_st

Answer 5

no... look down the g(x) column 1st... what is the lowest value...?

Answer 6

-3

Answer 7

great and the x value associated with is it -1

so g(x) has a minimum at (-1, -3)

Answer 8

so is this algebra or calculus..?

Answer 9

thank uu

Answer 10

algebra

Answer 11

well you have to look at f(x) as well

Answer 12

ok for f(x) you need to

find the line of symmetry, the minimum value lies on the line of symmetry

so use

\[x = \frac{-b}{2 \times a}\]

your f(x) has b = -8 and a = 2

can you substitute them and calculate a value for x

Answer 13

x=-2

Answer 14

@campbell_st

Answer 15

not quite its x = 2

\[x = \frac{-(-8)}{2 \times 2} = 2\]

so substitute x = 2 into f(x) and calculate a value... this will be the minimum for f(x)

Answer 16

im confused

Answer 17

find

\[f(2) = 2\times 2^2 - 8 \times 2 + 1\]

Answer 18

-7

Answer 19

@campbell_st

Answer 20

ok... so now which point is lower

(2, -7) or (-1, -3)...?

Answer 21

2,-7

Answer 22

there's your answer

Answer 23

thanks

Answer 24

u think u can help with a few more

Answer 25

@campbell_st

Answer 26

no, i'm about to go to school... its friday morning in Australia

Answer 27

oh ok

Answer 28

thx anyways