Question

In a certain coffee shop, a large latte costs 2 dollars more than a medium latte, and a medium latte costs 2 dollars more than a small latte. If 12 small lattes cost 2x dollars, how much will 5 large and 7 medium lattes cost?

A. 2x + 24
B. 2x + 34
C. 2x + 48
D. 12x + 24
E. 24x + 3

Answer 1

@jim_thompson5910

Answer 2

what does x represent?

Answer 3

I don't know. That is confusing me.

Answer 4

cost of large latte? medium? or small?

Answer 5

Can we assume that x=6?

Answer 6

where are you getting that?

Answer 7

nvm

Answer 8

S = cost of small
M = cost of medium
L = cost of large

Answer 9

`a large latte costs 2 dollars more than a medium latte`

so L = M+2

agreed?

Answer 10

yes

Answer 11

` medium latte costs 2 dollars more than a small latte`

using the variables I set up, what equation do you get?

Answer 12

S = x
M = x + 2
L = 2 + (x + 2) or 4 + x

Answer 13

S = unknown (not x)
M = S + 2
L = M + 2 = (S+2) + 2 = S + 4


`12 small lattes cost 2x dollars`

12S = 2x
S = (2x)/(12)
S = x/6

`how much will 5 large and 7 medium lattes cost?`

5L + 7M = 5(S+4) + 7(S+2)

Answer 14

the next step is to plug S = x/6 into 5(S+4) + 7(S+2)

Answer 15

so we are learning about plugging in numbers. can we work around that level?

Answer 16

you mean replacing S with some number like 7?

Answer 17

yeah

Answer 18

how would you get to the answer? each answer has an x in it

Answer 19

so can we like plug in 7 for x?

Answer 20

I am really confused on this.

Answer 21

Do you see how I got 5(S+4) + 7(S+2) ?

Answer 22

yes

Answer 23

\[\Large 5(S+4) + 7(S+2) = 5(\frac{x}{6}+4) + 7(\frac{x}{6}+2) \]

\[\Large 5(S+4) + 7(S+2) = 5(\frac{x}{6})+5(4) + 7(\frac{x}{6})+7(2) \]

\[\Large 5(S+4) + 7(S+2) = \frac{5x}{6}+20 + \frac{7x}{6}+14 \]

I'll let you simplify

Answer 24

12x/6 + 34

Answer 25

12x/6 simplifies to ???

Answer 26

2x

Answer 27

THANK YOU!!!

Answer 28

so 2x+34 is the answer

Answer 29

np

Answer 30

I have another question

Answer 31

If \[a = 2x + 3 \] and \[b = 4d\] what is b in terms of a?
A. \[(a - 3)^2\]
B.\[2(a - 3)^2\]
C. \[\frac{ (a-3)^2 }{ 4 }\]
D. \[\frac{ (a + 3)^2 }{ 4 }\]
E. \[a + 3\]

Answer 32

b = 4d? is that a typo?

Answer 33

Yes sorry \[b = 4d^2\]

Answer 34

and a = 2x + 3 is correct? or no?

Answer 35

that's correct

Answer 36

I don't see how to connect a and b. They have no variables in common

Answer 37

i have checked with many numbers none of which seems to work

Answer 38

something seems missing

Answer 39

i will check on that with my teacher. thank you :)

Answer 40

np