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OpenStudy (anonymous):
What is the factored form of 64g^3 +8? Fan and Medal
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OpenStudy (anonymous):
OpenStudy (anonymous):
the answers are below
OpenStudy (anonymous):
\[a^3+b^3=\left( a+b \right)\left( a^2-ab+b^2 \right)\]
OpenStudy (anonymous):
what is a?
OpenStudy (anonymous):
@surjithayer
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OpenStudy (anonymous):
\[64g^3=\left( 4g \right)^3\]
OpenStudy (anonymous):
\[8=2^3\]
OpenStudy (usukidoll):
are you there @rose49 ?
OpenStudy (anonymous):
is it d
OpenStudy (usukidoll):
\[64g^3+8\]
hints: both of these terms have a number in common
what is 8 x 8 ?
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OpenStudy (anonymous):
64
OpenStudy (usukidoll):
oh sorry this is sum of cubes.
yes 8 x 8 = 64 but I misread the question by accident
OpenStudy (usukidoll):
sum of cubes formula
\[(a+b)(a^2-ab+b^2) \]
OpenStudy (usukidoll):
so we need to write this equation..
what is the cube root of 8 and the cube root of 64?
OpenStudy (anonymous):
2^3
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OpenStudy (campbell_st):
64 = 4 x 4 x 4
g^3 = g x g x g
the problem is the sum of of 2 cubes
8 = 2 x 2 x 2
so the factored form is
\[a^3 + b^3 = (a + b)(a^2 -ab + b^2)\]
OpenStudy (anonymous):
wouldn't it be d
OpenStudy (usukidoll):
and cube root of g^3 ?
OpenStudy (usukidoll):
\[64g^3 + 8 \rightarrow (4g)^3+2^3\]
so a = 4g and b = 2
plug this into the sum of cubes equation
OpenStudy (anonymous):
i did and i got the answer d was i wrong?
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OpenStudy (usukidoll):
I don't think so.. I think you're right but just to be sure
\[(4g+2)((4g)^2-4g(2)+4)\]
OpenStudy (usukidoll):
\[(4g+2)(16g^2-8g+4)\]
OpenStudy (usukidoll):
yeah it is d
OpenStudy (anonymous):
okay thank you for the help i have one more to ask about
OpenStudy (usukidoll):
sure
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