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OpenStudy (anonymous):

What is the factored form of 64g^3 +8? Fan and Medal

OpenStudy (anonymous):

OpenStudy (anonymous):

the answers are below

OpenStudy (anonymous):

\[a^3+b^3=\left( a+b \right)\left( a^2-ab+b^2 \right)\]

OpenStudy (anonymous):

what is a?

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

\[64g^3=\left( 4g \right)^3\]

OpenStudy (anonymous):

\[8=2^3\]

OpenStudy (usukidoll):

are you there @rose49 ?

OpenStudy (anonymous):

is it d

OpenStudy (usukidoll):

\[64g^3+8\] hints: both of these terms have a number in common what is 8 x 8 ?

OpenStudy (anonymous):

64

OpenStudy (usukidoll):

oh sorry this is sum of cubes. yes 8 x 8 = 64 but I misread the question by accident

OpenStudy (usukidoll):

sum of cubes formula \[(a+b)(a^2-ab+b^2) \]

OpenStudy (usukidoll):

so we need to write this equation.. what is the cube root of 8 and the cube root of 64?

OpenStudy (anonymous):

2^3

OpenStudy (campbell_st):

64 = 4 x 4 x 4 g^3 = g x g x g the problem is the sum of of 2 cubes 8 = 2 x 2 x 2 so the factored form is \[a^3 + b^3 = (a + b)(a^2 -ab + b^2)\]

OpenStudy (anonymous):

wouldn't it be d

OpenStudy (usukidoll):

and cube root of g^3 ?

OpenStudy (usukidoll):

\[64g^3 + 8 \rightarrow (4g)^3+2^3\] so a = 4g and b = 2 plug this into the sum of cubes equation

OpenStudy (anonymous):

i did and i got the answer d was i wrong?

OpenStudy (usukidoll):

I don't think so.. I think you're right but just to be sure \[(4g+2)((4g)^2-4g(2)+4)\]

OpenStudy (usukidoll):

\[(4g+2)(16g^2-8g+4)\]

OpenStudy (usukidoll):

yeah it is d

OpenStudy (anonymous):

okay thank you for the help i have one more to ask about

OpenStudy (usukidoll):

sure

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