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HELP: the two small plastic spheres are arranged so that they can slide freely along the insulating fiber. Each has a mass of 0.1g. The spheres are given identical positive charges. a. If the lower sphere is resting against the lower knot while the upper sphere moves to a location 6 cm distant from that knot, find the charge on each. (the fiber is 45 degrees from the positive x-axis)
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my current solution is F=mg=weight=(0.0001)(9.8)=9.8x10^(-4) solving for the force along the fiber F=(9.8x10^(-4))/(sin(45))=1.3859x10^(-3)
I think you should ask this question in physics section..
oh... sorry...
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