Question

@mathmate

Answer 1

factoring by grouping


2x^+4x+1+4

Answer 2

my answer is (2x+1)(x+2)(x+4)

Answer 3

@mathmate @welshfella

Answer 4

@DarkMoonZ

Answer 5

Need help?

Answer 6

yes plz

Answer 7

I like your answer, it looks good to me.

Answer 8

7th advanced, you?

Answer 9

Oh really?

Answer 10

I was in public school advanced too.

Answer 11

@OregonDuck
If the answer is (2x+1)(x+2)(x+4)
the question should have been 2x^3+13x^2+22x+8
Do you still want to know \(how\) to solve it?

Answer 12

yes plz

Answer 13

@mathmate yes plz

Answer 14

We note that all coefficients are positives, therefore so are the factors.
The leading coeff. is 2, and the constant term is 8, so the possible factors are
1/2, 1,2,4, and 8.
we can try group them assuming a factor of x+2
2x^3+13x^2+22x+8
=2x^3+4x^2 + 9x^2+18x + 4x+8
=2x^2(x+2) + 9x(x+2) + 4(x+2)
and it seems to work well, so
=(x+2)(2x^2+9x+4)
factor the quadratic the same way, if you want:
=(x+2)(2x^2+8x + x+4)
=(x+2)(x+4)(2x+1)

Answer 15

so (x+2)(x+4)(2x+1) is the answer?

Answer 16

Yes, for the following question:
2x^3+13x^2+22x+8

Answer 17

NO WHAT IS THE ANSWER FOR 2x^+4x+1+4

Answer 18

you cannot factor
2x^+4x+1+4
because it is not a polynomial.
exponent is missing, and I suspect there are typos. Please check the question.

Answer 19

It also shows that you have not made any attempt to solve the problem, when you have posted your question for over half an hour and not realize that there are typos.

Answer 20

no 2x^2+4x+1+4

Answer 21

Are you sure about the +1+4 part?
The problem could have been written 2x^2+4x+5

Answer 22

yes i am sure

Answer 23

There are no rational factors for the problem 2x^2+4x+5.

Answer 24

k if it was written this way then the answer would be?

Answer 25

There are no rational factors for the problem 2x^2+4x+5.

Answer 26

then my answer was right then for 2x^+4x+1+4 right?

Answer 27

or prime?

Answer 28

what was your answer?

Answer 29

(2x+1)(x+2)(x+4)

Answer 30

#CAUGHT XD you got the answer and now you are presenting it here lol

Answer 31

Your "answer" expands to a cubic polynomial.
You're given a quadratic polynomial to factor, so your "answer" cannot be right.
I already gave you the question that corresponds to your "answer".

Answer 32

http://openstudy.com/study#/updates/55b25896e4b0ce10565f5149

Answer 33

so it is prime?

Answer 34

There are no rational factors, as I said earlier.

Answer 35

Just to satisfy my curiosity, can you tell me how you obtained the answer
(2x+1)(x+2)(x+4)
to
"factor 2x^+4x+1+4" ?

Answer 36

The reason I said there are no rational factors is because the expression
2x^2+4x+5
can be factored into
(x+1+sqrt(3/2)i)(x+1-sqrt(3/2)i)
where i is the complex number where i^2=-1
by completing the square!