Mathematics
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oregonduck (oregonduck):
2x^+4x+1+4
FACTORING BY GROUPING
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pooja195 (pooja195):
\[\huge~\rm~2x^2+4x+1+4?\]
pooja195 (pooja195):
is it like that?
oregonduck (oregonduck):
YES
pooja195 (pooja195):
Combine Like Terms:
=2x2+4x+1+4
=(2x2)+(4x)+(1+4)
=2x2+4x+5
oregonduck (oregonduck):
no factor like grouping is what i am trying to do
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oregonduck (oregonduck):
factoring by grouping
pooja195 (pooja195):
Then we do this
|dw:1437751547065:dw|
oregonduck (oregonduck):
?
oregonduck (oregonduck):
just tell be the steps to find the answer
pooja195 (pooja195):
have you ever seen this ?
\(\huge\color{purple}{ax^2+bx+c}\)
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oregonduck (oregonduck):
yes
pooja195 (pooja195):
That is known as standered form
when factoring by grouping we multiply a and c
pooja195 (pooja195):
have you ever seen this ?
\(\huge\color{red}{2x^2+4x+5}\)
oregonduck (oregonduck):
yes
pooja195 (pooja195):
lol my typos >_<
ok multiply...
\[\huge~\rm~5 \times 2=?\]
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OpenStudy (anonymous):
10
OpenStudy (anonymous):
XD
oregonduck (oregonduck):
10
OpenStudy (hybrik):
@pooja195 He is asking by grouping
OpenStudy (hybrik):
@OregonDuck You asked this question before
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OpenStudy (anonymous):
pooja the english chat nowwwwww
oregonduck (oregonduck):
@mathmate said that that answer is wrong so i am trying to get it checked
OpenStudy (hybrik):
@OregonDuck It was wrong before because you said a different terms
pooja195 (pooja195):
Actually this isnt even facotralbe
OpenStudy (hybrik):
This question can be 2x(x+2) and 5
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pooja195 (pooja195):
It would be prime :/
@hybrik i know that he was asking to do it by grouping this is that way i was taught.
OpenStudy (hybrik):
Im getting (2x+5)(x+2)
OpenStudy (hybrik):
@pooja195 I think its prime too, let me check
pooja195 (pooja195):
its prime you cant factor this
OpenStudy (hybrik):
As I checked, you can go to 2x2+4x+5, but, its prime,
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pooja195 (pooja195):
Right so @OregonDuck its prime which means not factor-able
oregonduck (oregonduck):
ok