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Mathematics 17 Online
OpenStudy (unofficialllyy):

can someone please help?

OpenStudy (unofficialllyy):

A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: Which of the following could be used to calculate the total volume of grains that can be stored in the silo?

OpenStudy (danjs):

If i am picturing the thing right, it is the vvolume of a cylinder plus the volume of the cone

OpenStudy (danjs):

|dw:1437755024017:dw|

OpenStudy (unofficialllyy):

OpenStudy (danjs):

Yes Total Volume = Volume Cylinder + Volume Cone

OpenStudy (danjs):

Cylinder - height = 8 ft , radius = 2 ft Cone - height = 1.5 ft, radius = 2 ft

OpenStudy (unofficialllyy):

I got \[\pi(2ft)^2(8ft)+\frac{ 1 }{ 3 } \pi(2ft)^2(9.5ft-8ft)\]

OpenStudy (danjs):

\[Volume = [\pi*r^2*h _{cyl}] + [\frac{ 1 }{ 3 }\pi*r^2*h _{cone}]\]

OpenStudy (danjs):

yep, looks good

OpenStudy (unofficialllyy):

Could you help me with some more?

OpenStudy (danjs):

sure

OpenStudy (unofficialllyy):

What is the weight (in grams) of a liquid that exactly fills a 202.0 milliliter container if the density of the liquid is 0.685grams over milliliter? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point.

OpenStudy (danjs):

weight = newtons, mass= grams.

OpenStudy (danjs):

nvm

OpenStudy (danjs):

Given: Volume = 202.0 mL Density = 0.685 g / mL Find: mass [g]

OpenStudy (danjs):

Density = mass / volume so mass = density * volume

OpenStudy (unofficialllyy):

I'm really confused lol

OpenStudy (danjs):

Just remember, the density is a mass per unit of volume Density = mass / volume

OpenStudy (danjs):

multiplying both sides by volume mass = volume x density

OpenStudy (unofficialllyy):

I got 138.37

OpenStudy (danjs):

|dw:1437755681677:dw|

OpenStudy (danjs):

right

OpenStudy (unofficialllyy):

I have one more that I need help with.

OpenStudy (danjs):

sure

OpenStudy (unofficialllyy):

A cone has a diameter of 8 centimeters and a height that is 4 times the diameter. Using 3.14 for pi, which of the following can be used to calculate the volume of the cone?

OpenStudy (anonymous):

i agree with you because you work really explains well

OpenStudy (danjs):

v = (1/3) * pi * r^2 * h

OpenStudy (danjs):

diameter = 8, so radius = 4 height = 4*diameter = 4*8 = 32

OpenStudy (unofficialllyy):

My answer is: \[\frac{ 1 }{ 3 }(3.14)(8cm)^2(32cm)\]

OpenStudy (danjs):

yep, and as a check, your units come out to cm^3 which is correct for a Volume

OpenStudy (anonymous):

yep

OpenStudy (unofficialllyy):

thank you so much!

OpenStudy (danjs):

no prob , anytime

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