Question

Help me simplify this equation? I'm garbage with this kind of math.

Answer 1

\[\sqrt{(x2-3)^2+(y2-0)^2} = \sqrt{(y2-1)^2}\]

Answer 2

I think what I do next is
\[(x2-3)^2+(y2-0)^2 = (y2-1)^2\]

Answer 3

by definition\[\sqrt{x^2} = \left| x \right|\]

Answer 4

I'm sorry, but how does that apply to this equation? I'm not a math person.

Answer 5

Because from what I've done so far I guess I would do this. In this case y1=0 which I think is throwing me off a little.
\[(x _{2})^2+y _{2}^3+0=(y _{2}-1)^2\]

Answer 6

Then I would do the same to the other side?
\[(x _{2})^2+y _{2}^3=y _{2}^2-2y _{2}+1\]

Answer 7

\[\sqrt{(x^2-3)^2 +(y^2)^2}= \sqrt{(y^2-1)}\]

Answer 8

is this the question?

Answer 9

Yes.

Answer 10

if so then it would be
\[(x^2-3)+ y^2= y^2-1\]