Mathematics
24 Online
OpenStudy (anonymous):
Let f(x) = x^2 + x + 2 and g(x) = 2x^2 + 5. Find f(g(x)). Show each step of your work.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@Vocaloid I just need to learn how to do the problem, not the answer.
Nnesha (nnesha):
replace x in f(x) function by g(x)
OpenStudy (anonymous):
I did that, I got: (2x^2+5)^2+2x^2+2
Nnesha (nnesha):
you forgot something \[ \huge\rm (2x^2+5)^2+\color{blue}{x}+2\]
x = 2x^2 + 5
Nnesha (nnesha):
you forgot 5
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
did I? Sorry.
OpenStudy (anonymous):
So to solve, is it 2x^4 or 4x^4
Nnesha (nnesha):
\[ \huge\rm (2x^2+5)^2+\color{blue}{2x^2 +5}+2\]
Nnesha (nnesha):
\[ \huge\rm \color{reD}{x^2}+\color{blue}{x}+2\]
\[ \huge\rm \color{ReD}{(2x^2+5)^2}+\color{blue}{2x^2 +5}+2\]
x is 2x^2 + 5
OpenStudy (anonymous):
Yes, so now we have to square x.
Join the QuestionCove community and study together with friends!
Sign Up
Nnesha (nnesha):
yes( 2x^2 +5)^2 is same as (2x^2 +5) (2x^2 +5) so foil it
OpenStudy (anonymous):
\[4x^4+20x^2+25\]
OpenStudy (anonymous):
right?
Nnesha (nnesha):
yes that's right
OpenStudy (anonymous):
So now we combine like terms?
Join the QuestionCove community and study together with friends!
Sign Up
Nnesha (nnesha):
yesp
OpenStudy (anonymous):
\[4x^4+20x^2+25+2x^2+5+2\]
OpenStudy (anonymous):
turns into
OpenStudy (anonymous):
\[4x^4+22x^2+32\]
OpenStudy (anonymous):
Right?
Join the QuestionCove community and study together with friends!
Sign Up
Nnesha (nnesha):
yep
OpenStudy (anonymous):
So now I need to factor?
Nnesha (nnesha):
nope that's ur answer
OpenStudy (anonymous):
Oh, is it? Good, my problem was I tried factoring that and had no idea how to do it.
OpenStudy (anonymous):
Thanks! :D
Join the QuestionCove community and study together with friends!
Sign Up
Nnesha (nnesha):
my pleasure
and yes that's it
they wants us to find f(g(x)) not factoring
OpenStudy (anonymous):
I fanned, so if I need anything, I'll make sure to tag you.
Nnesha (nnesha):
thanks i'll try my best :=)
OpenStudy (anonymous):
@Nnesha I have one more problem that seems pretty easy.
OpenStudy (anonymous):
I think I may know how to solve it but graphing and radicals are my weakpoint.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Describe how to transform \[(\sqrt[6]{x ^{5}})^{7}\] into an expression with a rational exponent
Nnesha (nnesha):
alright remember this exponent rule \[\huge\rm \sqrt[m]{x^n} = x^\frac{ n }{ m }\] you can convert root to exponent form
OpenStudy (anonymous):
Yes I know this, it would be \[(x^\frac{ 5 }{ 6 })^7\]
OpenStudy (anonymous):
then you multiply 7 and 5?
Nnesha (nnesha):
yep! right you already know
Join the QuestionCove community and study together with friends!
Sign Up
Nnesha (nnesha):
\[\huge\rm (x^m)^n = x^{ m \times n}\]
OpenStudy (anonymous):
\[x^\frac{ 35 }{ 6 }\]
OpenStudy (anonymous):
thats a 35/6 btw
Nnesha (nnesha):
yep
OpenStudy (anonymous):
And that is my answer?
Join the QuestionCove community and study together with friends!
Sign Up
Nnesha (nnesha):
yep right
OpenStudy (anonymous):
K, thanks. Just wanted to check my answer.
Nnesha (nnesha):
your answer is correct you're a mathematician :=)