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how would you find the x an y intercepts of y=xsqrrt16-x^2 ?
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the y intercepts is when x = 0 so plug in x = 0 into the function and work it out
to find the x intercepts sole xsqrrt16-x^2 = 0
you will put y as equal to zero and then \[\sqrt{16}-x^{2}\] x will be 4 and -4
i'm assuming there are parentheses around the 16 - x^2
the x intercepts will be 4 and -4 but also 0.
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xsqrrt(16-x^2) = 0 x = 0 , x^2 - 16 = 0 x^2 = 16 so x = 4 ,-4
y intercept = 0* sqrt16 = ?
yint=0 ?
yes
thank you so much!
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yw
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