Question

how would you find the x and y intercepts of y=x^2+x-2?

Answer 1

Well the easiest way would to be by graphing the function, but if we cant do that we can always algebraically figure it out

Answer 2

how would you solve graphically? I know the first step is to make either x or y equal 0

Answer 3

** I mean algebraically

Answer 4

Well you are correct that is how we do it

To solve for the 'y intercept' we make x = 0

\(\large y = 0^2 + 0 - 2 \) meaning that \(\large y = ?\)

Answer 5

-2

Answer 6

Right

And now the x-intercept would be making y = 0

So

\[\large 0 = x^2 + x - 2\]

We can factor this or just brute force through it

Answer 7

to find the y-intercept we let x = 0
to find the x-intercept we let y = 0

so when x = 0, y = -2 so that would mean that our y-intercept is at (0,-2)

Answer 8

we can factor \[\large 0 = x^2 + x - 2 \]. and then solve for x. We would have more than one solution for our x-intercepts

Answer 9

thank you both!

Answer 10

so we need to focus on the last term 2 and the second term 1
there's only one combination
2 x 1 = 2 (so we got the last term)
we need to use subtraction to obtain one
2-1 =1
so we have
\[\large 0 = (x+2)(x-1)\]

Answer 11

now we just split this up and solve for x in each case
\[\large 0 = x-1\],\[\large 0 = x+2 \]

Answer 12

so xint= -2 and 1 ?

Answer 13

yes our x = -2 and x = 1
so our x-intercepts are
(-2,0) and (1,0)
because we need y = 0 to obtain the x-intercepts.

Answer 14

first put y=0
so your equation will be0=x^2+x−2
then you will make it (x-1)(x+2)=0
so it will lead that x is equal to
1 and -2