Question

2x^4 + 2x^2 +32 can you break this down any farther? Help will be rewarded

Answer 1

well first take 2 out
= 2(x^4 + x^2 + 16)

Answer 2

why would you take the 2 out its attached to the x squared

Answer 3

2 is the GCF of 2, 2 and 32

Answer 4

but the expression in the parentheses won't factor

Answer 5

you've lost me and I just realized I forgot to include this f(g(x)) = and then the problem

Answer 6

I've already solved for most of the problem would it help if I gave you the original problem?

Answer 7

lets have the whole problem then

Answer 8

yes

Answer 9

okay give me a sec

Answer 10

Let f(x) = x2 + x + 2 and g(x) = 2x2 + 5. Find f(g(x)). Show each step of your work.

Answer 11

oh ok
what you do is replace very occurrence of x in f(x) by g(x)

Answer 12

Plug in the g(x) equation where all the x's are in f(x). (2x^2 + 5)^2 + (2x^2 + 5) + 2 2x^4 + 5^2 + 2x^2 + 5 + 2
2x^4 + 25 +2x^2 + 7
2x^4 + 2x^2 + 32

Answer 13

f(x) = x2 + x + 2
f((g(x)) = (2x^2 + 5)^2 + 2x^2 + 5 + 2
= 4x^4 + 20x^2 + 25 + 2x^2 + 7
= 4x^4 + 22x^2 + 32

Answer 14

you didnt expand (2x^2 + 5)^2 correctly

Answer 15

Thank you, so the 22 and 4 cannot be combined becuase of the different exponents right?

Answer 16

right

Answer 17

Thank you thank you thank you thank you!!!!!!!!

Answer 18

yw lol