A third-degree polynomial has 4 intercepts. A third-degree function can have as many as 3 zeros only true or false for both
False True
explanation?
@Mertsj
A third degree polynomial might be (x+1)(x-2)(x+3)=0 That would have three roots, that is 3 x intercepts.
If you have another root, there would be another factor and hence it would be a 4th degree polynomial.
In the following, p will be used to represent the polynomial, so we have p = a_0 + a_1 x + .... + a_n x^n. A root of the polynomial p is a solution of the equation p = 0, that is a number a such that p(a) = 0. The fundamental theorem of algebra combined with the factor theorem states that the polynomial p has n roots, if they are counted with their multiplicities.
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