Using the completing-the-square method, find the vertex of the function f(x) = –3x2 + 6x − 2 and indicate whether it is a minimum or a maximum and at what point.
i know you first put it in vertex form, but then how do you decide the max or mini thing
https://www.khanacademy.org/math/algebra/quadratics/features-of-quadratic-functions/v/ex3-completing-the-square Here's a video on how to do them
@mollzlask do you know how to find a vertex?
once you get it in vertex form, yes
how about with the formula \(x=\dfrac{-b}{2a}\)
oh lol how
so with that the vertex is 1,1 right?
the original equation is \(ax^2+bx+c=0\) in the equation you have, a = -3 , b = 6 , c = -2
yes the vertex is 1,1
okay, so is that the minimum then?
look at a in your equation if it is positive, then it opens upwards and (1,1) is the minimum if it is negative, then it opens downwards and (1,1) is the maximum
so what do you have as a in your equation?
its positive
first tell me what a is in your equation
it's the coefficient of \(x^2\)
3
oh wait lol
it has a negative sign in front of it
im stupid im sorry
no it's fine
so it is -3
thank you for helping me!!
np so since a is negative, the parabola would open downwards, and (1,1) would be the maximum.
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