Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

For the function y = f(x), what is the ordered pair for the point on the graph when x = 3n - 4?

OpenStudy (anonymous):

(3n - 4, f(n)) (3n - 4, f(3n - 4)) (x, f(3n)) (x, 3n - 4)

OpenStudy (solomonzelman):

For a function y=f(x), when x=2, my ordered pair would be \((2,~f(2))\). Do you agree with that?

OpenStudy (solomonzelman):

And same thing is when x=3n-4, except that instead of a 2 I got \(\small3{\rm n}-4\).

OpenStudy (anonymous):

mhm okay yea i understand

OpenStudy (anonymous):

so its d right

OpenStudy (solomonzelman):

no

OpenStudy (solomonzelman):

let me ask you again. I have a function y=f(x), and my x=4, what is the ordered pair?

OpenStudy (anonymous):

\[(4,f4)\]

OpenStudy (solomonzelman):

yes, \(\color{blue}{(4,f(4))}\)

OpenStudy (solomonzelman):

Ok, now my function is still f(x), but my x=8b what is my ordered pair then?

OpenStudy (anonymous):

\[(8b, f(8b))\]?

OpenStudy (solomonzelman):

yes, that is right

OpenStudy (solomonzelman):

now, my function is still f(x), and my x=3n-4 my ordered pair is?

OpenStudy (anonymous):

\[(3n-4 , f(3n-4))\]

OpenStudy (solomonzelman):

yes, that is right....

OpenStudy (anonymous):

so b is the answer

OpenStudy (solomonzelman):

yes, B is the answer.

OpenStudy (anonymous):

Awesome thank you so much again ! ;p

OpenStudy (solomonzelman):

yw

OpenStudy (anonymous):

could you help me with this one

OpenStudy (anonymous):

The table below represents the velocity of a car as a function of time: Time (second) x Velocity (m/s) f (x) 15 45 22 66 29 87 36 108 The average rate of change of the function between x = 15 to x = 29 is __________m/s2 and represents the car's acceleration.

OpenStudy (anonymous):

OpenStudy (anonymous):

thats the table

OpenStudy (anonymous):

I'm thinking the answer is 32 but im not so sure

OpenStudy (solomonzelman):

ok, you have two points (15,45) and (29,87) all you need to do is to find the slope. |dw:1437936165499:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!