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Mathematics 14 Online
OpenStudy (ashking1):

can someone help me Write the expression in standard form.

OpenStudy (ashking1):

\[\frac{ 5 }{ 3-15i }\]

OpenStudy (anonymous):

standard form is ax+by=c

OpenStudy (anonymous):

standrd form should be a + bi

OpenStudy (anonymous):

Oh I am thinking of a graph yeah I think you are right @d3v13

OpenStudy (anonymous):

so basically multiply both the sides by something to get that form

OpenStudy (ashking1):

so what do i multiply it by

OpenStudy (danjs):

(3 + 15i )/(3 + 15i) recall i^2 = -1

OpenStudy (danjs):

\[\frac{ 5 }{ (3-15i )}*\frac{ (3 + 15i) }{ (3 + 15i) } =\]

OpenStudy (danjs):

You don't want an imaginary number in the bottom, so switch the sign and multiply by the conjugate thing

OpenStudy (danjs):

you good ?

OpenStudy (ashking1):

oa ya but how does that equal to a fraction \[\frac{ 5 }{ 78 } -\frac{ 25 }{ 78}i\] \[\frac{ 5 }{ 78 } +\frac{ 25 }{ 78}i\] \[-\frac{ 5 }{ 78 } +\frac{ 25 }{ 78}i\] \[-\frac{ 5 }{ 78 } -\frac{ 25 }{ 78}i\] these are my choices

OpenStudy (danjs):

you need to multiply those two fractions ...

OpenStudy (danjs):

\[\frac{ 5(3+15i) }{ (3-15i)(3+15i) }=\]

OpenStudy (danjs):

remember i^2 = -1

OpenStudy (danjs):

\[\frac{ 5(3+15i) }{ (3-15i)(3+15i) }= \frac{ 15 + 75 i }{9 -15i + 15i -225*(-1) } =\]

OpenStudy (danjs):

whats next?

OpenStudy (ashking1):

ok i got that

OpenStudy (danjs):

\[\frac{ 15 + 75i }{ 234 }\]

OpenStudy (danjs):

just have to reduce the fractions.

OpenStudy (ashking1):

\[\frac{ 15 + 75 i }{9 + 225 }\]

OpenStudy (ashking1):

234 sorry

OpenStudy (danjs):

\[\frac{ 15 + 75i }{ 234 } = \frac{ 15 }{ 234 } + \frac{ 75i }{ 234 }\]

OpenStudy (ashking1):

simplify

OpenStudy (danjs):

yes, just reduce the fractions

OpenStudy (ashking1):

\[\frac{ 5 }{ 78 } +\frac{ 25 }{ 78}i\]

OpenStudy (danjs):

yep, standard form --- a + b*i

OpenStudy (ashking1):

thanks

OpenStudy (danjs):

welcome

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