Question

HELP MEDALS N FAN
34. Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit?

57

46

115

58

36. Two resistors of resistances 6 Ω and 12 Ω are connected in parallel across a 6 V battery. What is the equivalent resistance and total current in the circuit?


4 Ω; 1.5 A

18 Ω; 1.5 A

18 Ω; 0.34 A

4 Ω; 0.7 A

Answer 1

i need 36

Answer 2

parallel resistance:
\[R = \frac{ 6 \times 12 }{ 6+12 }\]

Answer 3

then use V = IR for the current

Answer 4

what is I and R?

Answer 5

is that 6 and 12

Answer 6

r is resistance, I is current. The 6 and 12 come from the resistors in the problem

Answer 7

4 Ω; 1.5 A
is this the answer

Answer 8

yes or no is ok

Answer 9

yes

Answer 10

thank u

Answer 11

No. 34. To solve this doe the following steps
1. Use Ohm's law and solve for the total resistance, I = 2 Amp, E = 115 volts

2. In series the resistances add. So divide the total resistance obtained in step 1 by the resistance of a single bulb. That is result will be the number of bulbs.

Answer 12

Ohm's Law: E = IR or voltage equal to current (i) times Resistance (R)