Mathematics
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OpenStudy (anonymous):
Can i have some help with this?
√75 + √3
11 years ago
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OpenStudy (anonymous):
does it help to know that \(75=25\times 3\)?
11 years ago
OpenStudy (anonymous):
use the website mathway!
11 years ago
OpenStudy (anonymous):
so \[\sqrt{75}=\sqrt{25\times 3}=\sqrt{25}\times \sqrt3\]
11 years ago
OpenStudy (anonymous):
you can enter in the equation and it gives you the answer
11 years ago
OpenStudy (anonymous):
you end up with
\[5\sqrt3+\sqrt3\] combine like terms to finish
11 years ago
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OpenStudy (anonymous):
Thanks @ihenandezzi but i'm trying to learn how to do the problem, besides i have the link :)
11 years ago
OpenStudy (anonymous):
@satellite73 wouldn't the like term make 6 or do i just write it out and don't add them?
11 years ago
OpenStudy (anonymous):
Anyone?
11 years ago
OpenStudy (solomonzelman):
ok, we got to the point of \(5\sqrt{3}+\sqrt{3}\).
11 years ago
OpenStudy (solomonzelman):
Do you know what is 5x+x ?
11 years ago
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OpenStudy (anonymous):
7?
11 years ago
OpenStudy (solomonzelman):
5x+x=5x+1x=6x
---------------
11 years ago
OpenStudy (solomonzelman):
is that correct?
11 years ago
OpenStudy (anonymous):
Yeah
11 years ago
OpenStudy (blake4560):
yes, 5x+x=6x
11 years ago
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OpenStudy (solomonzelman):
5x+x=6x
and same way, it follows that
5√3 + √3 = ?
11 years ago
OpenStudy (anonymous):
5√6
11 years ago
OpenStudy (solomonzelman):
no
11 years ago
OpenStudy (solomonzelman):
you are not adding inside the square root
11 years ago
OpenStudy (anonymous):
So i don't add the 3's
11 years ago
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OpenStudy (solomonzelman):
you are adding the "square-root-of-3" five times, PLUS "square-root-of-3" one time.
11 years ago
OpenStudy (blake4560):
isn't it \[5\sqrt{3}\]
11 years ago
OpenStudy (solomonzelman):
\(5\sqrt{3}+\sqrt{3}=5\sqrt{3}+1\sqrt{3}=?\)
11 years ago
OpenStudy (anonymous):
I don't know. guessing 2?
11 years ago
OpenStudy (solomonzelman):
5+1=?
11 years ago
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OpenStudy (anonymous):
6
11 years ago
OpenStudy (solomonzelman):
5a+1a=?
11 years ago
OpenStudy (blake4560):
6a
11 years ago
OpenStudy (solomonzelman):
5(something) + 1(something) = ?
11 years ago
OpenStudy (anonymous):
Depends on the something.
11 years ago
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OpenStudy (solomonzelman):
6(something)
11 years ago
OpenStudy (solomonzelman):
5(something) + 1(something) = 6(something)
(as long as we are talking about the same something)
11 years ago
OpenStudy (solomonzelman):
5√3 + 1√3 = ?
11 years ago
OpenStudy (anonymous):
Think i said 6..
11 years ago
OpenStudy (solomonzelman):
5√3 + 1√3 = 6 ?
11 years ago
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OpenStudy (anonymous):
5√6
11 years ago
OpenStudy (anonymous):
1√3
11 years ago
OpenStudy (solomonzelman):
5 + 1 = 6
5x + 1x = 6x
5 bees + 1 bee = 6 bees
5a + 1a = 6a
5√3 + 1√3 = 6√3
compare these
11 years ago
OpenStudy (anonymous):
6√6
11 years ago
OpenStudy (solomonzelman):
why?
11 years ago
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OpenStudy (anonymous):
3+3 5+1 6,6
11 years ago
OpenStudy (solomonzelman):
you are adding the number of times of which you have a √3.
you have five square roots of 3, and then you add one more square root of 3.
how many square roots of 3 do you have together?
11 years ago
OpenStudy (anonymous):
6<---
11 years ago
OpenStudy (solomonzelman):
yes, so
5√3 + 1√3 = ?
11 years ago
OpenStudy (anonymous):
Do we add the 3's?
11 years ago
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OpenStudy (anonymous):
if so that would be 6√6
11 years ago
OpenStudy (solomonzelman):
we don't add the square root inside, just 5√3+1√3=(5+1)√3 = 6√
11 years ago
OpenStudy (solomonzelman):
6√3
11 years ago
OpenStudy (anonymous):
Okay.
11 years ago