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OpenStudy (anonymous):
If c(x) = 4x – 2 and d(x) = x2 + 5x, what is c(d(x))
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OpenStudy (anonymous):
hey you again :D
Nnesha (nnesha):
ello same question :=)
OpenStudy (anonymous):
so just do the same thing?
Nnesha (nnesha):
yes right
OpenStudy (anonymous):
but x is already x so would it be 2x^2 + 5x^2 in the D function?
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Nnesha (nnesha):
that would be the same so just replace x in c(x) function by d(x)
Nnesha (nnesha):
\[\huge\rm c(\color{ReD}{d(x)}) = c(\color{Red}{x^2+5x}) =4\color{reD}{x}-2\]
OpenStudy (anonymous):
so am i just simplifying x^2+5x=4x-2?
Nnesha (nnesha):
no
you need to
plug x^2+5x into the x
c(x^2+5x) is same as c(d(x))
Nnesha (nnesha):
4x -2
^^^ that x replace by x^2 +5x
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OpenStudy (anonymous):
ohhh
OpenStudy (anonymous):
4x^2 + 3
Nnesha (nnesha):
mhm.. how did you get that ?
OpenStudy (anonymous):
4 and x^2 combine then 5-2
Nnesha (nnesha):
remember when multiply same bases we should add their exponents \[\huge\rm x^m \times x^n = x^{m+n}\]
and on't forget the parenthesis
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Nnesha (nnesha):
it should be like this \[\huge\rm 4(x^2+5x)-2\]
distribute parentheses by 4 and then combine like terms
OpenStudy (anonymous):
ohh i forgot parentheses
OpenStudy (anonymous):
4x2+20x−2??
Nnesha (nnesha):
:=) right
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