A state vector X for a four-state Markov chain is such that the system is four times as likely to be in state 3 as in 4, is not in state 2, and is in state 1 with probability 0.2. Find the state vector X.

Question

anonymous · Answer

The probability of all states add up to $1$. Let $a$ be the probability of state 4. $$
0.2 + 0 + 4a + a =1
$$If you solve for $a$, then you can use: $$
X = \begin{bmatrix}0.2 \ 0 \ 4a \ a\end{bmatrix}
$$

anonymous · Answer

There is already an open question that has the same problem as yours. :O

anonymous · Answer

http://openstudy.com/study#/updates/55b5b91de4b0d48ca8eeed71

unklerhaukus · Answer

hmmm