Question

What is the phase shift for the equation: y=-3sec(π-2x)+5

Answer 1

@pooja195 @Hero @e.mccormick @SolomonZelman

Answer 2

this equation can be written as y=5-3sec(-2x+pi)
where the phase shift would be -2x+pi=0

Answer 3

solve for x ...and thats ur phase shift

Answer 4

what do u get?

Answer 5

2x/pi

Answer 6

no -2x+pi=0
-2x=-pi
divide by -2
x=pi/2

Answer 7

so the phase shift is pi/2

Answer 8

yep

Answer 9

wait I have one more question, is there a such thing of having a phase shift of 0 or is that considered not a phase shift @LynFran

Answer 10

not a phase shift .....a phase shift mean that there a vertical shift ...either to the right or left of the graph

Answer 11

\[y=-2\sin(5/4x) \]

Answer 12

and that new phase shift determines where the graph starts

Answer 13

^Does that equation have no phase shift then^

Answer 14

yes that equation has no phase shift

Answer 15

it just have the amplitude which is |-2|=2
and its period which is 2pi divided by 5/4x

Answer 16

thank you so much

Answer 17

wait I thought the amplitude would just be -2

Answer 18

the amplitude does not have absolute value

Answer 19

F(t) = Af(Bt – C) + D, A is the ampitude

Answer 20

no amplitudes are always the absolute value of the # infront the function /curve .... which means its always positive...

Answer 21

i think that you are wrong

Answer 22

@ganeshie8

Answer 23

check this out http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U19_L2_T3_text_final.html

Answer 24

OH WAIT YOU ARE RIGHT, I WAS THINKING ABOUT PERIODICITY

Answer 25

IM SO SORRY

Answer 26

@LynFran

Answer 27

its ok