Find the surface area of the composite solid. Round your answer to the nearest hundredth.
The total surface area of the composite solid, can be decomposed into three areas: 1 the circular base 2 the lateral surface area of the cylinder (a rectangle) & 3 the lateral area of the cone (a sector)
The area of a circle (or radius \(r\)) is : \[A_\text{circle} = \pi r^2\]
The area of a rectangle (of width \(w\), height \(h\)) is: \[A_\text{rectangle} = w\times h\]
so i tryed it and got c is that right
i don't know,
that makes to of us
The area of the sector (of radius \(r\), and slope \(s\)) is: \[A_\text{sector} = \pi r s\]
add them all together, what do you get ? (before plugging in the numbers)
i put c and i only got 30 min :( and got 6 more questions
i dont know what the answer is, we have to work it out
\[SA_\text{total} = A_\text{circle}+A_\text{rectangle}+A_\text{sector}\\ \qquad\quad= \quad. . .\]
never mind that one i guessed cuz ii need to do the rest befopre time runs out
NB: the width of the rectangle the circumference of a circle \[w =C = 2\pi r\]
\[SA_\text{total} = A_\text{circle}+A_\text{rectangle}+A_\text{sector}\\ \qquad\quad= \pi r^2+2\pi r h+\pi rs\\ \qquad\quad= \pi r(r+2h+s)\\ \qquad\quad= \quad. . .\]
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