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Mathematics 19 Online
OpenStudy (chancemorris123):

Find the surface area of the composite solid. Round your answer to the nearest hundredth.

OpenStudy (chancemorris123):

OpenStudy (unklerhaukus):

The total surface area of the composite solid, can be decomposed into three areas: 1 the circular base 2 the lateral surface area of the cylinder (a rectangle) & 3 the lateral area of the cone (a sector)

OpenStudy (unklerhaukus):

The area of a circle (or radius \(r\)) is : \[A_\text{circle} = \pi r^2\]

OpenStudy (unklerhaukus):

The area of a rectangle (of width \(w\), height \(h\)) is: \[A_\text{rectangle} = w\times h\]

OpenStudy (chancemorris123):

so i tryed it and got c is that right

OpenStudy (unklerhaukus):

i don't know,

OpenStudy (chancemorris123):

that makes to of us

OpenStudy (unklerhaukus):

The area of the sector (of radius \(r\), and slope \(s\)) is: \[A_\text{sector} = \pi r s\]

OpenStudy (unklerhaukus):

add them all together, what do you get ? (before plugging in the numbers)

OpenStudy (chancemorris123):

i put c and i only got 30 min :( and got 6 more questions

OpenStudy (unklerhaukus):

i dont know what the answer is, we have to work it out

OpenStudy (unklerhaukus):

\[SA_\text{total} = A_\text{circle}+A_\text{rectangle}+A_\text{sector}\\ \qquad\quad= \quad. . .\]

OpenStudy (chancemorris123):

https://www.youtube.com/watch?v=Qmb9cnx__hA

OpenStudy (chancemorris123):

never mind that one i guessed cuz ii need to do the rest befopre time runs out

OpenStudy (unklerhaukus):

NB: the width of the rectangle the circumference of a circle \[w =C = 2\pi r\]

OpenStudy (unklerhaukus):

\[SA_\text{total} = A_\text{circle}+A_\text{rectangle}+A_\text{sector}\\ \qquad\quad= \pi r^2+2\pi r h+\pi rs\\ \qquad\quad= \pi r(r+2h+s)\\ \qquad\quad= \quad. . .\]

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