help please, check the attachment, thank you!!

Question

anonymous · Answer

attachment

anonymous · Answer

attachment

usukidoll · Answer

given
yogurt sundae represented by x and costs $4
yogurt cone represented by y and costs $3
we got a $50 card
it's like the equation is 4x+3y=50
so that could be 
4x+3y < 50
4x+3y > 50
$$4x+3y \leq  50$$
or
$$4x+3y \geq  50 $$

anonymous · Answer

do you know which one of the graphs it would be? @UsukiDoll I'm stuck between A and C

usukidoll · Answer

I haven't done this in years, so I'm thinking xD

anonymous · Answer

@UsukiDoll lol thanks for trying

usukidoll · Answer

you have to graph the line of 4x+3y = 50 first

usukidoll · Answer

change it to the y =mx+b form

jim_thompson5910 · Answer

Let T be the total cost of buying x sundaes and y cones

Since you only have $50, this means that is the most you can spend. It is the ceiling. So that's why $$\Large T \le 50$$ T could be less than 50 or it could be equal to 50.

1 sundae costs $4, so x of them cost 4x dollars
1 cone costs $3, so y of them cost 3y dollars
buying x sundaes and y cones gives a total of 4x+3y dollars, so T = 4x+3y

Plug that into the inequality
$$\Large T \le 50$$
$$\Large 4x+3y \le 50$$

usukidoll · Answer

ah .. I might have overlooked that $50 limit... so we have to be less than $50 or equal to $50 for this... And since we have $$\LARGE \leq $$, it's a solid line

usukidoll · Answer

so the dash choices are out. 

now let's pick a test point like the origin (0,0) also known as x = 0 and y =0 and plug it into the equation to see if the inequality is true or false
$$\Large 4x+3y \le 50 $$
letting x = 0 and  y = 0 

$$\Large 4(0)+3(0) \le 50 $$
$$\Large 0+0 \le 50 $$
$$\Large 0 \le 50 $$

since 0 is less than or equal to 50. we have to shade the line that includes (0,0)

usukidoll · Answer

your graph should look like this