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Algebra 14 Online
OpenStudy (anonymous):

suppose f(x)=x^3+1. find the graph of f(2x)

OpenStudy (anonymous):

i don't understand it at all

OpenStudy (usukidoll):

we are given the function \[f(x) =x^3+1 \] that should be graphed first and then we apply the f(2x) in this case x = [2x] into the original function and that modification should be graphed second.

OpenStudy (arindameducationusc):

I agree with @UsukiDoll

OpenStudy (usukidoll):

:) thank you @arindameducationusc

OpenStudy (welshfella):

the graph will be a stretch of factor 2 of f(x) parallel to the y-axis.

OpenStudy (anonymous):

OpenStudy (welshfella):

which one has that stretch?

OpenStudy (anonymous):

i think the third down

OpenStudy (arindameducationusc):

This should help for more....

OpenStudy (welshfella):

well its not easy to see unless you have the graph of x^3 + 1 also

OpenStudy (anonymous):

true

OpenStudy (welshfella):

ff(2x) will bring the graph closer to the y-axis. It will still go through the point (0,1)

OpenStudy (welshfella):

i think its B

OpenStudy (welshfella):

- but you really need to draw them to make sure

OpenStudy (usukidoll):

graph f(x) = x^3+1 and then apply the f(2x) your modified function should look like this f(2x)=8x^3+1

OpenStudy (welshfella):

yes

OpenStudy (welshfella):

to see the graphs go the desmos calculator web site

OpenStudy (welshfella):

very roughly the graphs are |dw:1437999923777:dw|

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