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OpenStudy (anonymous):
i don't understand it at all
OpenStudy (usukidoll):
we are given the function
\[f(x) =x^3+1 \]
that should be graphed first
and then we apply the f(2x) in this case x = [2x] into the original function and that modification should be graphed second.
OpenStudy (arindameducationusc):
I agree with @UsukiDoll
OpenStudy (usukidoll):
:) thank you @arindameducationusc
OpenStudy (welshfella):
the graph will be a stretch of factor 2 of f(x) parallel to the y-axis.
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OpenStudy (anonymous):
OpenStudy (welshfella):
which one has that stretch?
OpenStudy (anonymous):
i think the third down
OpenStudy (arindameducationusc):
This should help for more....
OpenStudy (welshfella):
well its not easy to see unless you have the graph of x^3 + 1 also
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OpenStudy (anonymous):
true
OpenStudy (welshfella):
ff(2x) will bring the graph closer to the y-axis. It will still go through the point (0,1)
OpenStudy (welshfella):
i think its B
OpenStudy (welshfella):
- but you really need to draw them to make sure
OpenStudy (usukidoll):
graph f(x) = x^3+1
and then apply the f(2x)
your modified function should look like this
f(2x)=8x^3+1
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OpenStudy (welshfella):
yes
OpenStudy (welshfella):
to see the graphs go the desmos calculator web site