suppose f(x)=x^3+1. find the graph of f(2x)
i don't understand it at all
we are given the function \[f(x) =x^3+1 \] that should be graphed first and then we apply the f(2x) in this case x = [2x] into the original function and that modification should be graphed second.
I agree with @UsukiDoll
:) thank you @arindameducationusc
the graph will be a stretch of factor 2 of f(x) parallel to the y-axis.
which one has that stretch?
i think the third down
This should help for more....
well its not easy to see unless you have the graph of x^3 + 1 also
true
ff(2x) will bring the graph closer to the y-axis. It will still go through the point (0,1)
i think its B
- but you really need to draw them to make sure
graph f(x) = x^3+1 and then apply the f(2x) your modified function should look like this f(2x)=8x^3+1
yes
to see the graphs go the desmos calculator web site
very roughly the graphs are |dw:1437999923777:dw|
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