Question

An atom emits a photon of wavelength 1.08 meters. What is the energy change occurring in the atom due to this emission? (Planck's constant is
6.626 × 10-34 joule seconds, the speed of light is 2.998 × 108 m/s)

Answer 1

\[E=hf\]
\[but f=\frac{ v }{ \lambda } \]

Answer 2

\[E=h \frac{ v }{ \lambda } \]
E= 18.3932 x 10 ^ - 26