Question

54,55,59,61,61,62,68,70,72 how do i find the irst quartile, median, third quartile, and maximum of the data set?

Answer 1

the first quartile can be found using this formula \[\frac{ 1 }{ 4 }(n+1)\]

Answer 2

n=9

Answer 3

9/4?

Answer 4

since there 9 #s in the set

Answer 5

Okay

Answer 6

\[\frac{ 1 }{ 4 }(9+1)\]

Answer 7

1/4(9+1

Answer 8

1 can't be divided by 4 can it?

Answer 9

Do i move the 9+1 over the 4.

Answer 10

u will get \[\frac{ 1 }{ 4 }(10)\]\[2.5th value\] the average 2nd and 3rd values are 55 and 59 so \[\frac{ 55+59 }{ 2 }=?\]

Answer 11

Lagging

Answer 12

55+59/2=57 now 57 is ur 1st quartile value

Answer 13

Okay. what is the 2.5th value?

Answer 14

thats the average where u will find ur two numbers for the fisrt quartile

Answer 15

so in this set of numbers the first quartile is between the the 2nd and 3rd #

Answer 16

Okay

Answer 17

so we add the 2nd and 3rd # and then divide the # by 2

Answer 18

okay would that be 54 and 55?

Answer 19

no thats the 1st and 2nd # ... u need the 2nd and 3rd #

Answer 20

so 55 and 59?

Answer 21

yes now add them

Answer 22

100 +14
114

Answer 23

59+55=114
now we divide by 2

Answer 24

114/2=?

Answer 25

57

Answer 26

good now 57 is ur 1st quartile

Answer 27

Alright.

Answer 28

to find the median we located the middle value in the set....what # is in the middle?

Answer 29

61?

Answer 30

correct

Answer 31

to find the 3rd quartile the formula is \[\frac{ 3 }{ 4 }(n+1)th . value \]

Answer 32

\[\frac{ 3 }{ 4 }(9+1)th.value\]

Answer 33

What do i do first add the 9+1 will give me 10 but what do i do next?

Answer 34

\[\frac{ 3 }{4 }(10)th.value\]\[\frac{ 30 }{ 4 }th. value\]7.5 th. value so the 3rd quartile is between the 7th and 8th numbers

Answer 35

Oh so we time it by 3
3*10 = 30 /4

Answer 36

7th and 8th what does that mean?

Answer 37

we locate the 7th and 8th #s in the data/set

Answer 38

whats the 7th and 8 number frm the set

Answer 39

Okay.

Answer 40

68 and 70

Answer 41

good now add them and divide by 2

Answer 42

138/2 = 69

Answer 43

good thats ur 3rd quartile

Answer 44

So we should be done.

Answer 45

whats the maximum?

Answer 46

Not sure. ^ ^;

Answer 47

72..

Answer 48

DX Ahh.

Answer 49

Okay thanks.

Answer 50

here more info on quartiles with a similar example http://www.mathsteacher.com.au/year9/ch17_statistics/06_quartiles/quartiles.htm

Answer 51

welcome

Answer 52

Thanks for the link too.

Answer 53

the 2nd quatile \[\frac{ 2 }{ 4 }(10)th.value \]= 5th. value so the 5th value is 61 and yes 61 is the 2nd quartile

Answer 54

Alright thanks.