Question

You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five.

What is the probability of drawing a red four and then a blue four, while replacing the card between the drawings?



A company has determined that 1% of its widgets are defective.

If a customer received 2 widgets, what is the probability that they are both defective?

Answer 1

@jcoury

Answer 2

Do you know about the pigeonhole principle?

Answer 3

@OregonDuck

Answer 4

the odds in drawing the red 4 is 1 in 10, so to get it would be 1/10.
the odds are the same for getting the blue 4, so again, it's 1/10.

Because this is a probability of two simultaneous events, you have to multiply the probabilities.

So, (1/10)(1/10) = 1/100. Your answer is A.

Answer 5

Where did you get A from, i don't see any choices?

Answer 6

Assume independence because there are probably a lot of widgets.

1/100 x 1/100 = 1/10,000

How do I get the 1/100?

From 1%

1% = 0.01 = 1/100

Answer 7

i have had this question before and before that choice was a so i thought i was a

Answer 8

wow

Answer 9

yup
i am pretty fast

Answer 10

yeah all your catoriges have to move up for your mian number to change

Answer 11

how do i get more engagement?

Answer 12

i have not moved up in a while but i have answered so many questions and i found out i need 8 more medals

Answer 13

k

Answer 14

Your dedication and engagement when learning on OpenStudy