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The temperature of 6.24 L of a gas is increased from 25.0°C to 55.0°C at constant pressure. The new volume of the gas is A. 13.7 L. B. 5.67 L. C. 6.87 L. D. 2.84 L.
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You can use the formula V1/T1=V2/T2 Temperature needs to be in Kelvin (so add 273 to both) T1 is the initial temperature Vi is the initial volume T2 is final temperature V2 is final volume and the one that you will solve for
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