The molar heat of vaporization for methane, CH4, is 8.53 kJ/mol. How much energy is absorbed when 54.8 g of methane vaporizes at its boiling point?
Use q = n triangle H.

6.42 kJ
29.1 kJ
137 kJ
467 kJ

Question

The molar heat of vaporization for methane, CH4, is 8.53 kJ/mol. How much energy is absorbed when 54.8 g of methane vaporizes at its boiling point? 
Use q = n triangle H.

6.42 kJ
29.1 kJ
137 kJ
467 kJ

taramgrant0543664 · Answer

To start you take the mass so 54.8g divided by the molar mass of methane this will give you the moles which is the n value.
delta (the triangle) mean change in this will be the 8.53kJ/mol
To find q you just have to multiply the moles you find by 8.53