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Mathematics 20 Online
OpenStudy (empty):

How do I find the inverse function of $$f(x)=x^5+x$$

OpenStudy (jtvatsim):

The standard method is to replace the f(x) with a x and each x with a y. Then, solve for y. However, it seems like this would be a bit messy in this case... still thinking here.

OpenStudy (astrophysics):

Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x) Yeah I don't think this will work well

OpenStudy (jtvatsim):

And I'm assuming the question is to find the actual equation of the inverse correct?

OpenStudy (empty):

Yeah this is my question haha.

OpenStudy (jtvatsim):

Obviously, I just said that because if we only need the graph, we can just reflect over y = x and obtain the visual solution. :)

OpenStudy (astrophysics):

Hey quick question, so this function is 1 - 1 right

OpenStudy (jtvatsim):

agreed

OpenStudy (freckles):

We can invent a new function and call it the freckles function where the freckles function is the inverse function of f(x)=x^5+x. I guess that is what Lambert did.

OpenStudy (jtvatsim):

LOL

OpenStudy (jtvatsim):

Clearly, the inverse does exist, so we can call it whatever we want right? :)

OpenStudy (empty):

hahaha :)

OpenStudy (dan815):

how about polar coords

OpenStudy (empty):

I like what @freckles is saying but I'm not sure if I like this answer I want something more algebraic.

OpenStudy (dan815):

what we're looking for is a way to write out the inverse function with one equation without having to deal with the +/- sqrts right

OpenStudy (jtvatsim):

Is there a way to do it with +/- sqrts?

OpenStudy (dan815):

i dunno i didnt really do anything i just saw it had powers in it so lol

OpenStudy (freckles):

@Empty do you have an answer and are challenging us, or is this something you wanted to explore with us while challenging yourself and us?

OpenStudy (usukidoll):

@freckles probably the second option

OpenStudy (dan815):

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