A culture started off with 5000 bacteria after 5 hours it grew too 6500 bacteria predict how many bacteria will be present after 16 hours
P=Ae^kt formula

Question

A culture started off with 5000 bacteria after 5 hours it grew too 6500 bacteria predict how many bacteria will be present after 16 hours 
P=Ae^kt formula

taramgrant0543664 · Answer

So you have to find k first so it started with 5000 so that's A
P would be 6500 and t is 5 and you solve for k
6500=5000e^k(5)

taramgrant0543664 · Answer

Once you find the k value then you can use that as k, use 5000 as A and your t would be 16 and you would solve for P

anonymous · Answer

Well how do I find out what k is?

taramgrant0543664 · Answer

6500=5000e^5k
6500/5000=e^5k
ln(6500/5000)=5k
ln(6500/5000)/5=k

anonymous · Answer

So k would be 1.3?

anonymous · Answer

Or 0.26?

taramgrant0543664 · Answer

No k=0.052 you didn't do the ln of it or divide by 5

taramgrant0543664 · Answer

(ln1.3)/5=0.052

taramgrant0543664 · Answer

ln is the inverse of e

anonymous · Answer

So my final equation would be p=5000e^0.052*16 ?

taramgrant0543664 · Answer

Yes and solving for p is the answer you want

anonymous · Answer

Ok thanks you!(:

taramgrant0543664 · Answer

No problem happy to help!

anonymous · Answer

So it seems as if my answer is wrong, what should I get for the answer?

taramgrant0543664 · Answer

What did you get?

anonymous · Answer

1195.48, I don't see how I got this

taramgrant0543664 · Answer

I got 11489.6

anonymous · Answer

Alright, I guess I'll just have to keep trying, thanks for the help though(: