Physics
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OpenStudy (anonymous):
Question
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OpenStudy (anonymous):
OpenStudy (anonymous):
@dan815
OpenStudy (dan815):
ok yep?
OpenStudy (dan815):
what is the question
OpenStudy (anonymous):
so when i put all the values in the calc i dont get excat answer as tht
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OpenStudy (dan815):
seems to be right
OpenStudy (anonymous):
no i mean the answer is right but this is what i get when i put in the excat value
OpenStudy (arindameducationusc):
what do you get?
OpenStudy (anonymous):
4.8705*10^-7
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OpenStudy (arindameducationusc):
okay lets do by this way.....
OpenStudy (arindameducationusc):
multiply by 4.14*3 . and in powers of 10, add -15 and 8, we get -7, isn't it
OpenStudy (anonymous):
ok
OpenStudy (arindameducationusc):
now 4.14*3 we get 12.4, now divide it by 2.55.
OpenStudy (arindameducationusc):
so total we have 4.87 * 10^-7, isn't it?
And you have a problem that it is 487, right?
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Nanometer is 10^-9, the answer you got was 10^-7, so just some need to do conversion and you get the numbers.
OpenStudy (arindameducationusc):
now listen carefully 1nm=10^-9m, right?
so,when we have 4.87*10^-7 if we take it to nanometer, 100 is multiplied to 4.87
OpenStudy (arindameducationusc):
and 100 is divided in 10th power to make it to nanometer.....
OpenStudy (arindameducationusc):
so, you get 487*10^-9, Got it?
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OpenStudy (anonymous):
is their a single number i can just times by
OpenStudy (arindameducationusc):
I didn't get you, single number?
OpenStudy (anonymous):
yea like when we have somthing in grams we just divide by 1000 to get in kg
OpenStudy (anonymous):
0.000000001
OpenStudy (arindameducationusc):
yes, yes
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OpenStudy (arindameducationusc):
10^-9 is 0.000000001
10^-7 is 0.0000001
OpenStudy (anonymous):
in my data shhet i have to h values one in ev and the other in J which one to use?
OpenStudy (arindameducationusc):
eV
OpenStudy (anonymous):
how know for sho
OpenStudy (arindameducationusc):
1eV=1.602*10^-19 J
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OpenStudy (arindameducationusc):
you can convert and write anyone.... its your choice....
OpenStudy (anonymous):
if the question is in ev then i use ev right
OpenStudy (arindameducationusc):
yes.. ofcourse
OpenStudy (arindameducationusc):
But you can use Joules, but it will just become complicated...
OpenStudy (arindameducationusc):
Got it?
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OpenStudy (anonymous):
yea
OpenStudy (anonymous):
i hav e anotehr
OpenStudy (anonymous):
i was doing these practive probs but wasnt getting the right answer doww
OpenStudy (anonymous):
frequineces required for photoelectron emsiion in 400 THz
OpenStudy (arindameducationusc):
ya, i will try ask
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OpenStudy (anonymous):
wavelength 500nm what is speed if excaping eletrons ?
OpenStudy (anonymous):
tell me waht u get for speed
OpenStudy (arindameducationusc):
from which orbit are the electrons escaping?
OpenStudy (anonymous):
doesnt say anthing else
OpenStudy (anonymous):
their was a work funstion 2.65*10^-19
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OpenStudy (arindameducationusc):
ya work function....
OpenStudy (arindameducationusc):
Wait
OpenStudy (arindameducationusc):
The minimum energy required to make an electron free from the metal is called the work function, right?
OpenStudy (anonymous):
ye
OpenStudy (arindameducationusc):
okay I got it....... use this
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OpenStudy (arindameducationusc):
hc/lambda=workfunction+K.E
OpenStudy (arindameducationusc):
K.E is kinetic energy
OpenStudy (arindameducationusc):
and K.E=1/2mv^2
OpenStudy (arindameducationusc):
so you can get v from here.... rest all data given h,c,lambda,mass of electron and work function
OpenStudy (arindameducationusc):
just plug in the values... you will get the answer. Got it?
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OpenStudy (anonymous):
Ek=hc/wavelenght
OpenStudy (anonymous):
i tried i didnt get btw what u get
OpenStudy (arindameducationusc):
so, do you have the answer with you? I will solve and ask you
OpenStudy (anonymous):
yes
OpenStudy (arindameducationusc):
9.33 * 10^21
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OpenStudy (arindameducationusc):
long calculation
OpenStudy (anonymous):
its 5.40*10^5
OpenStudy (arindameducationusc):
hmmm
OpenStudy (arindameducationusc):
but the process is this way.... well I was of no use... sorry... I did my best....