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OpenStudy (anonymous):

Question

OpenStudy (anonymous):

OpenStudy (anonymous):

@dan815

OpenStudy (dan815):

ok yep?

OpenStudy (dan815):

what is the question

OpenStudy (anonymous):

so when i put all the values in the calc i dont get excat answer as tht

OpenStudy (dan815):

seems to be right

OpenStudy (anonymous):

no i mean the answer is right but this is what i get when i put in the excat value

OpenStudy (arindameducationusc):

what do you get?

OpenStudy (anonymous):

4.8705*10^-7

OpenStudy (arindameducationusc):

okay lets do by this way.....

OpenStudy (arindameducationusc):

multiply by 4.14*3 . and in powers of 10, add -15 and 8, we get -7, isn't it

OpenStudy (anonymous):

ok

OpenStudy (arindameducationusc):

now 4.14*3 we get 12.4, now divide it by 2.55.

OpenStudy (arindameducationusc):

so total we have 4.87 * 10^-7, isn't it? And you have a problem that it is 487, right?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Nanometer is 10^-9, the answer you got was 10^-7, so just some need to do conversion and you get the numbers.

OpenStudy (arindameducationusc):

now listen carefully 1nm=10^-9m, right? so,when we have 4.87*10^-7 if we take it to nanometer, 100 is multiplied to 4.87

OpenStudy (arindameducationusc):

and 100 is divided in 10th power to make it to nanometer.....

OpenStudy (arindameducationusc):

so, you get 487*10^-9, Got it?

OpenStudy (anonymous):

is their a single number i can just times by

OpenStudy (arindameducationusc):

I didn't get you, single number?

OpenStudy (anonymous):

yea like when we have somthing in grams we just divide by 1000 to get in kg

OpenStudy (anonymous):

0.000000001

OpenStudy (arindameducationusc):

yes, yes

OpenStudy (arindameducationusc):

10^-9 is 0.000000001 10^-7 is 0.0000001

OpenStudy (anonymous):

in my data shhet i have to h values one in ev and the other in J which one to use?

OpenStudy (arindameducationusc):

eV

OpenStudy (anonymous):

how know for sho

OpenStudy (arindameducationusc):

1eV=1.602*10^-19 J

OpenStudy (arindameducationusc):

you can convert and write anyone.... its your choice....

OpenStudy (anonymous):

if the question is in ev then i use ev right

OpenStudy (arindameducationusc):

yes.. ofcourse

OpenStudy (arindameducationusc):

But you can use Joules, but it will just become complicated...

OpenStudy (arindameducationusc):

Got it?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

i hav e anotehr

OpenStudy (anonymous):

i was doing these practive probs but wasnt getting the right answer doww

OpenStudy (anonymous):

frequineces required for photoelectron emsiion in 400 THz

OpenStudy (arindameducationusc):

ya, i will try ask

OpenStudy (anonymous):

wavelength 500nm what is speed if excaping eletrons ?

OpenStudy (anonymous):

tell me waht u get for speed

OpenStudy (arindameducationusc):

from which orbit are the electrons escaping?

OpenStudy (anonymous):

doesnt say anthing else

OpenStudy (anonymous):

their was a work funstion 2.65*10^-19

OpenStudy (arindameducationusc):

ya work function....

OpenStudy (arindameducationusc):

Wait

OpenStudy (arindameducationusc):

The minimum energy required to make an electron free from the metal is called the work function, right?

OpenStudy (anonymous):

ye

OpenStudy (arindameducationusc):

okay I got it....... use this

OpenStudy (arindameducationusc):

hc/lambda=workfunction+K.E

OpenStudy (arindameducationusc):

K.E is kinetic energy

OpenStudy (arindameducationusc):

and K.E=1/2mv^2

OpenStudy (arindameducationusc):

so you can get v from here.... rest all data given h,c,lambda,mass of electron and work function

OpenStudy (arindameducationusc):

just plug in the values... you will get the answer. Got it?

OpenStudy (anonymous):

Ek=hc/wavelenght

OpenStudy (anonymous):

i tried i didnt get btw what u get

OpenStudy (arindameducationusc):

so, do you have the answer with you? I will solve and ask you

OpenStudy (anonymous):

yes

OpenStudy (arindameducationusc):

9.33 * 10^21

OpenStudy (arindameducationusc):

long calculation

OpenStudy (anonymous):

its 5.40*10^5

OpenStudy (arindameducationusc):

hmmm

OpenStudy (arindameducationusc):

but the process is this way.... well I was of no use... sorry... I did my best....

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