MEDAL! to first person to help me. help needed. question is in the comment box
A vertical shift adds/subtracts a constant to/from every y-coordinate while leaving the x-coordinate unchanged so our functions are either going up + sign or going down - sign if we have a horizontal shift we are either going left f(x+k) left k units or right f(x-k) right k units
there that should be the right graph
I've noticed something... while the shifts are different for the equation (g(x) is going up, and f(x) is going down) we have either a stretch or shrink depending on the number at the beginning of the function
for the f(x) function we have 1/2 if we have 0<x<1 it's compressed (shrink) for g(x) we have 1.5 or 3/2 for a number x>1 it stretches in the y-direction
so this is the original f(x) function and the graphs where the transformations are applied
and here we have the g(x) and its transformations so .. since we have 1/2 for f(x) and we have 3/2 for g(x) one of the graphs is shrinking and one is stretching.. not the same in that department either
I think it has something to do with the shifts that contain the parenthesis. I'm going to include the graphs with the ORIGINAL function (there were 3 graph transformations total). so all together f(x) and g(x) have four separate graphs
so A it stretches.
one graph stretches and the other one shrinks.. so it's not the same one graph goes up and the other one goes down ... not the same either the shifts inside the () is what they have in common
In function graphing, a horizontal translation is a transformation which results in a graph that is equivalent to shifting the base graph left or right in the direction of the x-axis.
ooh oke. c: thanks!
yes :) because I've noticed that there is a x-2 and x -7 and although one graph shifts 2 units to the right and the other graph shifts 7 units to the right, both of those graphs are going to the right. :)
(x-2), (x-7)
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