Question

Suppose a triangle has two sides of length 42 and 35, and that the angle between these two sides is 120. What is the length of the third side of the triangle?

Answer 1

help please

Answer 2

can you help?

Answer 3

hey m8

Answer 4

hmm i will try

Answer 5

Alright please

Answer 6

I am trying too...

Answer 7

Thank you both.

Answer 8

I am like stressing because of this test I cant pass

Answer 9

ok so you use the law of cosine i think

Answer 10

yea I did but I got lost after

Answer 11

\[c^2=a^2+b^2\]

Answer 12

oh i forgot the -2abcos(o)

Answer 13

anyways \[c^2=32^2+35^2−2(32)(35)\cos(120)\]

Answer 14

cos A=b^2+c^2-c^2/2ab This is the cosine formula, Isn't it? @Icedragon50

Answer 15

where did you get 32?

Answer 16

\[c^2=1024+1225-2240(-\frac{ 1 }{ 2 })=3369\]

Answer 17

c=\[√3369=58.04\]

Answer 18

and there ya go!

Answer 19

@arindameducationusc ya

Answer 20

Thank you so much m8

Answer 21

np :)

Answer 22

g'night I'm tired xD

Answer 23

Same its 1 lol

Answer 24

bout to play league of legends