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Mathematics 14 Online
OpenStudy (anonymous):

Algebra!!!

OpenStudy (anonymous):

The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t2 − 0.5t + 3.5 The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year.

OpenStudy (anonymous):

@Vocaloid @futurelegend @thomaster @LynFran

Vocaloid (vocaloid):

[f(6)-f(2)]/(6-2)

Vocaloid (vocaloid):

find f(6) and f(2), then plug them into the equation

OpenStudy (anonymous):

You need to take the derivatives. \[f'(t) = 0.5t -5\]

OpenStudy (anonymous):

Oh lord, I have no idea.

OpenStudy (anonymous):

Wait, is it 2?

OpenStudy (anonymous):

@saseal ? @Vocaloid ?

Vocaloid (vocaloid):

f(t) = 0.25t^2 − 0.5t + 3.5 f(6) = ?

OpenStudy (anonymous):

Yea, I suppose.

OpenStudy (anonymous):

OK.

OpenStudy (anonymous):

@DaBest21

OpenStudy (anonymous):

@ganeshie8 @Hero @ParthKohli @thomaster @triciaal @Michele_Laino @alekos

OpenStudy (michele_laino):

please see the procedure of @Vocaloid

OpenStudy (triciaal):

the average rate of change is like the slope of a best fit line slope of a line is change in y / corresponding change in x = y2 - y1 find the y value when x = 6 this is y2 find the y value when x = 2 this is y1 the change in x from 6 to 2 this is the same thing done above by @Vocaloid

OpenStudy (anonymous):

The line isn't straight, its a quadratic curve. \[f(t) = 0.25t ^{2} + 0.5t +3.5\]

OpenStudy (anonymous):

oops a typo in the function should be \[f(t) = 0.25t^2-0.5t+3.5\]

OpenStudy (anonymous):

What vocaloid found was the total change during the total period from t=2 to t=6, but the question asked for average rate of change from period t=2 to t=6.

OpenStudy (triciaal):

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