Question

There are seven black socks, eight blue socks, 10 white socks, and five patterned socks in the drawer. What is the probability of pulling a blue sock, replacing it, and then drawing a patterned sock out of the drawer?

Answer 1

@OregonDuck

Answer 2

Since there is replacement, the total no. of socks in the drawer does not change, therefore:

The probability of pulling a patterned sock on after the replacement= no. of patterned socks/total no. of socks = 5/30 = 1/6

Answer 3

7/30 it's 7 black socks

Answer 4

Wait no

Answer 5

im going to start putting the answers up lol 3/30 13/60 2/45 4/9

Answer 6

You was right

Answer 7

That would be helpful

Answer 8

well first of all there are 25 socks total/ Considering there are 8 blue socks you have a 8/25 chance of getting a blue sock and because you replace that sock there are still 25 socks and the odds of getting a patterned sock is 5/25. so we just multiply the two together 8/25 * 5/25 = 40/625 simplify to 8/125. I pretty sure that's the answer it's been awhile since I have done this.

Answer 9

Your right @OregonDuck

Answer 10

thats not a choice tho

Answer 11

@heretohelpalways

Answer 12

I am here

Answer 13

any idea?

Answer 14

yes, what is the probability of each event happening by itself?

Answer 15

1/30

Answer 16

and what are the options?

Answer 17

Ok it's 8 blue socks and 5 pattern socks

Answer 18

3/30 16/60 2/45 4/9

Answer 19

so if it is 8/30 probability for blue socks and 5/30 for patterned socks, multiply 8/30 by 5/30

Answer 20

The probability for picking blue and replacing it would be 13/30

Answer 21

? that would not work im so confused

Answer 22

30 divided by 13 is 2.4

Answer 23

still no :(

Answer 24

What are the options

Answer 25

ahhhhhhhhhhhh

Answer 26

so the answer would be 2/45

Answer 27

why would it be 2/45

Answer 28

@Owlcoffee

Answer 29

because 8/30*5/30=2/45

Answer 30

Yes heretohelpalways it right

Answer 31

C is the correct answer

Answer 32

to find the probability of a compound event, multiply each independent event

Answer 33

in this case, the independent event probabilities are 8/30 and 5/30