Question

An expression is shown below:

3x3y + 12xy - 9x2y - 36y

Part A: Rewrite the expression so that the GCF is factored completely. Show the steps of your work. (3 points)

Part B: Rewrite the expression completely factored. Show the steps of your work. (4 points)

Part C: If the two middle terms were switched so that the expression became 3x3y - 9x2y + 12xy - 36y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. (3 points)

Answer 1

Help plz

Answer 2

@madison.bush

Answer 3

hey

Answer 4

Part A: \[3y(x ^{3}+4x-3x ^{2}-12)\]

Part B: \[3y(x ^{2}+4)(x-3)\]

Answer 5

help with part c plz

Answer 6

@katt9421

Answer 7

Could you help with part c

Answer 8

the factored expression will still be equivalent to the answer in B. Moving the middle 2 terms makes no difference to the expression

Answer 9

if you plugged in say x=1 and y=2 into the 2 expression the result will be the same for both. Expressions may be written in different ways.

Answer 10

Part c: the factored expression will still be equivalent to the answer in B. Moving the middle 2 terms makes no difference to the expression.if you plugged in say x=1 and y=2 into the 2 expression the result will be the same for both. Expressions may be written in different ways.

Answer 11

Part A: Part A: 3x^3y+12xy−9x^2y−36y

GCF of numbers = 3
GCF of y terms = y

3x^3y+12xy−9x^2y−36y


after factoring the 3 :
3(x^3y+4xy−3x^2y−12y)

after factoring the y :
3y(x^3+4x−3x^2−12)

Answer: 3y(x^3+4x−3x^2−12)

Answer 12

Part B: 3y(x^3+4x−3x^2−12)

Factoring out GCF from first two terms gives :

3y(x(x^2+4)−3x^2−12)

3y(x^3+4x−3x^2−12)

Factoring out GCF from first two terms gives :
3y(x(x^2+4)−3x^2−12)

Factoring the GCF from last two terms gives :
3y(x(x^2+4)−3(x^2+4))

factoring out the (x^2+4) from the terms inside parenthesis gives :
3y(x^2+4)(x−3)