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Verify the identity. \[\cot \left( x-\frac{ \pi }{ 2 } \right)=-tanx\]
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I don't know if I should use cofunction identites because cot (pi/2-x) = tan x, but there's a negative sign.
\[\cot \left( x-\frac{ \pi }{ 2 } \right)=-tanx\]
use compound identity
What is that?
\[\frac{ \cos(x-\frac{ \pi }{ 2 }) }{ \sin(x-\frac{ \pi }{ 2 }) }\]
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Oh okay I get it now. Thank you!
\[\frac{ cosxcos \frac{ \pi }{ 2 }+sinxsin \frac{ \pi }{ 2 } }{ sinxcos \frac{ \pi }{ 2 }-cosxsin \frac{ \pi }{ 2 } }\]
\[\frac{ cosx(0)+sinx(1) }{sinx(0)-cosx(1) }\]
= - tan x yes good work LynFran
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