CAN SOMEONE TELL ME IF THESE ARE CORRECT!! ANWSER ARE ON THE BOTTOM Part A: Factor 3x2y2 − 2xy2 − 8y2. Show your work. Part B: Factor x2 + 10x + 25. Show your work. Part C: Factor x2 − 36. Show your work. -------------------- Part A-y^2(3x^2y^2-2x-8) Part B-(x+5)^2 Part C-(x+6)(x-6)
if you have 3 different typez of chocolates in the boxand u will take out all of 3 how many will left in the box ?
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yes right so factor menas take out common stuff right so first question when you take out y^2 from first term how many y will left in the parentheses \[\huge\rm 3x^2y^2 − 2xy^2 − 8y^2\]
or in other words divide all 3 terms by common factor
\[ \huge\rm \frac{ 3x^2y^2 }{ y^2 }-\frac{ 2xy^2 }{ y^2}-\frac{ 8y^2 }{ y^2 }\]
So the y^2 would cancel out?
YEP!
so y^2(??????????????)
so it would be 3x^2-2x-8?
btw Part B-(x+5)^2 \(\checkmark\) Part C-(x+6)(x-6) \(\checkmark\)
thank you
yep my pleasure
so the final answer would be 3x^2-2x-8
who kidnapped y^2 ??
y^2(3x^2-2x-8)
lO_Oks gO_Od
THANKKK YOUUU SOOO MUCHHHHH
hmmm
now factor 3x^2 -2x-8
hmmmm combine like terms first right?
are there any *like* terms ?
nope there are none
so i would apply *Headphone* method find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term a=leading coefficient b=middle term c=constant term
\[\huge\rm \color{reD}{A}x^2-\color{blue}{B}x-\color{green}{C }\] \[\huge\rm \color{reD}{3}x^2-\color{blue}{2}x-\color{green}{8 }\]
so suntract them?
no what is a and c ?
3-8?
yep a =3 and c=-8 so multiply them ac =3 times -8 = -24 find two number if you multiply them you should get -24 and if you add or subtract them you should get -2
so the answer is y^2(3x+4)(x-2)
yep that's right ..........
thankk youu
my pleasure
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